Given that
Dimensional and unit of magnetic field
∵  Force (F) =  charge × magnetic Fill d (B)×
velocity (v)

∴ magnetic $\text{ Field }\left(\mathrm{B}\right)=\frac{{\mathrm{f}}_{\mathrm{x}}}{\mathrm{q}\times \mathrm{v}}$   ----------------(1) ∵ velocity$=\frac{\text{ Distance }}{\text{ Time }}=\left[{\mathrm{LT}}^{-1}\right]$ 

∴ Charge = current × time =[IT]

∴ Force = mass × acceleration = [M]LT^–2

$\therefore \text{ magnetic field }=\frac{\text{ Force }}{\text{ Charge }+\text{ velocity }}$ 

$=\frac{\left[\mathrm{m}\right]\left[{\mathrm{LT}}^{-2}\right]}{\left[\mathrm{IT}\right]\left[{\mathrm{LT}}^{-1}\right]}={\mathrm{M}}^1{\mathrm{L}}^0{\mathrm{T}}^2{\mathrm{I}}^{-1}$ 

∴  magnetic field is represented as:-

m¹T^–2I^–1.

(where, m = mass, T = Time, I = Ampere]
In the SI System:
→ B is measured in Teslas → T
→ In Gaussion-cgs units, B is measured.

in gauss (symbolic)