Engineering
Physics
Projectile Motion
Question

Trajectory of two particles projected from origin with speed v1 and v2 and angle θ1 and θ2 with positive x-axis respectively as shown in the figure. Given that g=10m/s2(j^). Choose the correct option related to diagram.
 

v1 – v2 = 2v1

3(v1 – v2) = 2v1

θ2 – θ1 = 2θ1

3(θ2 – θ1) = θ1

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Solution
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10=v12sin2θ12g    ... (i)
40=v12sin22θ1g    ... (ii)
from (i) and (ii)
14=sinθ14cosθ1=tanθ14,  θ1=45°
10v12(1/2)2×10
v1 = 20 m/s
similarly for second particle
θ2 = 60° and v2 = 20 m/s

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