Three isomers A, B and C (mol. formula C8H11N) give the following results: A \textrm{ }\textrm{ } and \textrm{ }\textrm{ } C \rightarrow_{}^{Diazotization} P + Q \rightarrow_{\left(\right. ii \left.\right) \textrm{ }\textrm{ } oxidation \\ \left(\right. \left(KMnO\right)_{4} + H^{+} \left.\right)}^{\left(\right. i \left.\right) \textrm{ }\textrm{ } Hydrolysis} R \textrm{ }\textrm{ } \left(\right. product \textrm{ }\textrm{ } of \textrm{ }\textrm{ } A \left.\right) \\ + \\ S \textrm{ }\textrm{ } \left(\right. product \textrm{ }\textrm{ } of \textrm{ }\textrm{ } C \left.\right) R has lower boiling point than S B \rightarrow_{}^{C_{6} H_{5} \left(SO\right)_{2} Cl} alkali-insoluble product A, b and C, respectively are:

Engineering

Chemistry

Acid and Base GOC

Question

Three isomers A, B and C (mol. formula C₈H₁₁N) give the following results:

$A and C \to_{}^{Diazotization} P + Q \to_{\begin{array}{l} (ii) oxidation \\ ({KMnO}_{4} + H^{+}) \end{array}}^{(i) Hydrolysis} \begin{matrix} R (product of A) \\ + \\ S (product of C) \end{matrix}$

R has lower boiling point than S

B $\to_{}^{C_{6} H_{5} {SO}_{2} Cl}$ alkali-insoluble product A, b and C, respectively are:

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