The Wheatstone bridge shown in figure here, gets balanced when the carbon resistor used as R1 has the colour code (Orange, Red, Brown). The resistors R2 and R4 are 80 Ω and 40 Ω, respectively.Assuming that the colour code for the carbon resistors gives their accurate values, the colour code for the carbon resistor, used as R3, would be

Engineering

Physics

Ohm Law and Current Basics

Question

The Wheatstone bridge shown in figure here, gets balanced when the carbon resistor used as R₁ has the colour code (Orange, Red, Brown). The resistors R₂ and R₄ are 80 Ω and 40 Ω, respectively.

Assuming that the colour code for the carbon resistors gives their accurate values, the colour code for the carbon resistor, used as R₃, would be

Brown, Blue, Black

Brown, Blue, Brown

Red, Green, Brown

Grey, Black, Brown

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R₁ = 32 × 10 = 320 Ω

$R_{3} = \frac{R_{y}}{R_{2}} \times R_{1} = \frac{40 \times 320}{80} = 160 Ω$

∴ Colour code of R₃ be Brown, Blue, Brown.