The speed - time graph of a particle moving along a solid cover is shown below. The distance traversed by the particle from t = 0 to t = 3 is :-

Foundation

Physics Foundation

Vertical Motion

Question

$\frac{9}{2} m$

$\frac{9}{4} m$

$\frac{10}{3} m$

$\frac{10}{5} m$

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Distance covered is equal to the area under the graph in given interval of time.

\Rightarrow Distance = are a = \frac{1}{2} \times 3 \times 1.5 = \frac{9}{4} m

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