The order of the oxidation state of the phosphorus atom in H3PO2, H3PO4, H3PO3 and H4P2O6 is

Engineering

Chemistry

Oxidation Number and Calculation

Question

The order of the oxidation state of the phosphorus atom in H₃PO₂, H₃PO₄, H₃PO₃ and H₄P₂O₆ is

H₃PO₃ > H₃PO₂ > H₃PO₄ > H₄P₂O₆

H₃PO₄ > H₃PO₂ > H₃PO₃ > H₄P₂O₆

H₃PO₂ > H₃PO₃ > H₄P₂O₆ > H₃PO₄

H₃PO₄ > H₄P₂O₆ > H₃PO₃ > H₃PO₂

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H₃PO₂ H₃PO₄ H₃PO₃ H₄P₂O₆

4(+1) + 2x + 6(–2) = 0

2x = 8 ⇒ x = + 4

H₃PO₄ > H₄P₂O₆ > H₃PO₃ > H₃PO₂

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