Engineering
Physics
traaa
Question

The hodograph is a plot of velocity of the body on the x-y plane. The velocity vector of the body is drawn to scale such that its starting point is the origin. To illustrate the definition of hodograph, we take the case of a projectile projected under influence of gravity. Initially, the particle is moving at an angle θ to the horizontal with a velocity v0 as shown. As time passes, its velocity changes under the influence of constant acceleration g. By equation of motion, we can say v=v0+gt. Note that gt is always vertically downward. Here this velocity vector is drawn at 3 successive seconds. At the end of 3 seconds the velocity vector in this case becomes horizontal. This means that the body has reached the highest point. The trajectory is more difficult to work with because it is parabolic in shape.

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Linked Question 1

The hodograph for a projectile is shown here till it strikes the ground. This represents a projectile.

Projected on level ground with initial velocity of 10 m/s

Projected from a height with initial velocity of 20 m/s at 30° to horizontal.

Projected from a height with initial velocity of 10 m/s at 30° to horizontal

Projected from foot of an inclined plane on the inclined plane with initial velocity of 20 m/s at 30° to horizontal.

Solution
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v0 cos 30° = 10    
⇒    v0 = 20 m/s

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Linked Question 2

A particle is moving in a circular path with constant angular velocity ω, starting from A. ω is anticlockwise. Its hodograph for 1st quarter revolution is 

Solution
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Linked Question 3

The area of the triangle formed till any time is 

12g × horizontal displacement

g × magnitude of displacement

distance travelled by projectile × g

12g × vertical displacement 

Solution
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Area =12 v0 cos θ gt =12      (horizontal displacement) × g

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