The distance between an octahedral and tetrahedral void in fcc lattice would be

Engineering

Chemistry

Voids or Interstitial Site and Radius Ratio

Question

$\sqrt{3} a$

$\frac{\sqrt{3 a}}{2}$

$\frac{\sqrt{3 a}}{3}$

$\frac{\sqrt{3 a}}{4}$

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Distance between an octahedral and tetrahedral void in fcc lattice is = $\frac{body diagonal}{4} = \frac{\sqrt{3} a}{4}$

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