The circum radius of the triangle ABC is

Engineering

Mathematics

Family of Straight lines

Question

$\frac{17}{2}$

$\frac{65}{8}$

$\frac{63}{8}$

$\frac{33}{4}$

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Area of triangle $ABC = \frac{5 \cdot 12 + 12 \cdot 9}{2} = 30 + 54 = 84$

$∴ R = \frac{abc}{4 Δ} = \frac{13 \cdot 14 \cdot 15}{4 \cdot 84}$

$R = \frac{13 \cdot 15}{4 \cdot 6} = \frac{65}{8}$

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