The above p-v diagram represents the thermodynamic cycle of an engine, operating with an ideal monoatomic gas. The amount of heat, extracted from the source in a single cycle, is :

Engineering

Physics

Thermodynamics

Question

The above p-v diagram represents the thermodynamic cycle of an engine, operating with an ideal monoatomic gas. The amount of heat, extracted from the source in a single cycle, is :

$(\frac{13}{2}) p_{0} v_{0}$

p₀v₀

$(\frac{11}{2}) p_{0} v_{0}$

4p₀v₀

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Q_{given during isochoric & isobaric process}

$Q_{1} = {nCvΔT}_{1} = \frac{3}{2} {nRΔT}_{1} = \frac{3}{2} P_{0} V_{0}$

$Q_{2} = {nC}_{P} {ΔT}_{2} = \frac{5}{2} {nRΔT}_{2} = \frac{5}{2} \times 2 P_{0} \times V_{0}$

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