Statement-1 : A charge is outside the Gaussian sphere of radius R. Then electric field on the surface of sphere is zero. Statement-2 : As \oint E \cdot ds = \frac{qin}{\left(\epsilon\right)_{0}} , qin the sphere is zero so \oint E \cdot ds = 0

Engineering

Physics

Electric Field and Gauss Law

Question

Statement-1 : A charge is outside the Gaussian sphere of radius R. Then electric field on the surface of sphere is zero.

Statement-2 : As $\oint E \cdot ds = \frac{qin}{ε_{0}}$ , q_in the sphere is zero so $\oint E \cdot ds = 0$

Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for statement-1

Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1

Statement-1 is True, Statement-2 is False

Statement-1 is False, Statement-2 is True

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In Gauss Theroem

$φ = \oint \vec{E} \cdot d \vec{s} = \frac{q_{in}}{ε_{0}}$

$\vec{E}$ is due to all charges present inside (q_in) and outside (q_out)

But $\vec{E}$ due to q_out ≠ 0

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