Simplified absorption spectra of three complexes ((i) and (ii) and (iii)) of M+n ion are provided below; their λmax values are marked as A, B and C respectively. The correct match between the complexes and their λmax values is: (i) [M(NCS)6](–6 + n) (ii) [MF6](

Engineering

Chemistry

Laws of Chemical Combination

Question

Simplified absorption spectra of three complexes ((i) and (ii) and (iii)) of M⁺ⁿ ion are provided below; their λ_max values are marked as A, B and C respectively. The correct match between the complexes and their λ_max values is:

(i) [M(NCS)₆]^{(–6 + n)} (ii) [MF₆]^{(–6 + n)} (iii) [M(NH₃)₆]ⁿ⁺

A-(ii), (B)-(iii), C-(i)

A-(iii), (B)-(i), C-(ii)

A-(ii), (B)-(i), C-(iii)

A-(i), (B)-(ii), C-(iii)

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Stronger the ligand greater is splitting of d orbitals and smaller will be wave length of light absorbed. The splitting power of ligands is ${NH}_{3} < NC \bar{S} < F^{-}$

So order of wave length of light absorbed is $λ_{{NH}_{3}} < λ_{NC \bar{S}} < λ_{F^{-}}$

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