Oxidation state of S in H2S2O8 is:
Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.
Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA
The structure of H2S2O8 is given below.
H−O− –O – O– –O – H
In the structure of H2S2O8, two oxygen atoms are involved in peroxide linkage, hence oxidation number will be −1 (each). Remaining oxygen atoms will have −2 charge. Thus, we can calculate the oxidation state of sulphur ( x ) as follows:
H2S2O8 = 2 + 2 + 2 + 6 = 0 x = + 6.
Please subscribe our Youtube channel to unlock this solution.