In the given circuit, the AC source has = 100 rad/s. Considering the inductor and capacitor to be ideal, the correct choice(s) is(are)

Engineering

Physics

AC Circuit Analysis

LCR and Resonance in AC Circuit

Question

In the given circuit, the AC source has $ω$ = 100 rad/s. Considering the inductor and capacitor to be ideal, the correct choice(s) is(are)

The current through the circuit, I is 0.32 A

The voltage across 100 $Ω$ resistor $= 10 \sqrt{2} V$

The voltage across 50 $Ω$ resistor = 10 V

The current through the circuit, I is $0 .32 \sqrt{2} A$

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

$tan ϕ_{1} = \frac{X_{C}}{R_{1}} = 1$ $tan ϕ_{2} = \frac{X_{L}}{R_{2}} = 1$

$∴ ϕ_{1}$ = 45° $∴ ϕ_{2}$ = 45°

$I_{1} = \frac{20}{\sqrt{X_{c}^{2} + R_{1}^{2}}} = \frac{1}{5 \sqrt{2}}$ $I_{2} = \frac{20}{\sqrt{X_{L}^{2} + R_{2}^{2}}} = \frac{2}{5 \sqrt{2}}$

$∴ I = \sqrt{I_{1}^{2} + I_{2}^{2}} = \frac{1}{\sqrt{10}}$ $V_{L} = I_{2} X_{L} = 10 \sqrt{2}, V_{c} = I_{1} X_{c} = 10 \sqrt{2}$