In a triangle PQR, P is the largest angle and cos P = . Further the incircle of the triangle touches the sides PQ, QR and RP at N, L and M respectively, such that the lengths of PN, QL and RM are consecutive even integers. Then possible length(s) of the side(s) of the triangle is(are)
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cos p = = (4n + 2)2 + (4n + 4)2 – (4n + 6)2
2(4n + 2)(4n + 4)
⇒ (2n + 1)(n +1) = 3n2 = 3
⇒ n2 – 3n – 4 = 0
⇒ (n – 4)(n +1) = 0
n = 4
So sides are 18, 20, 22
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