Engineering
Mathematics
Basic Rules of Properties of Triangle
Question

In a triangle PQR, P is the largest angle and cos P =  13 . Further the incircle of the triangle touches the sides PQ, QR and RP at N, L and M respectively, such that the lengths of PN, QL and RM are consecutive even integers. Then possible length(s) of the side(s) of the triangle is(are)

24

16

18

22

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Solution

cos p = 13  = (4n + 2)2 + (4n + 4)2 – (4n + 6)2

2(4n + 2)(4n + 4)

 13=16(n21)16(2n+1)(n+1)

 ⇒   (2n + 1)(n +1) = 3n2 = 3

⇒   n2 – 3n – 4 = 0

⇒   (n – 4)(n +1) = 0

   n = 4

So sides are 18, 20, 22

  

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