For the circuit shown below, the current through the Zener diode is:

Engineering

Physics

Transistors

Question

5 mA

14 mA

Zero

9 mA

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$i_{10 k} = \frac{50}{10 k} = 5 mA$

$i_{5 k} = \frac{120 - 50}{5 k} = 14 mA$

i₂ = (14 5)mA = 9 mA

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