For hydrogenation of ethene into ethane as per following chemical reaction \left(CH\right)_{2} = \left(CH\right)_{2} + H_{2} \overset{Pd}{\rightarrow} \left(CH\right)_{3} - \left(CH\right)_{3} The ΔHreaction is written as Calculate ΔHreaction for

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Question

For hydrogenation of ethene into ethane as per following chemical reaction ${CH}_{2} = {CH}_{2} + H_{2} \overset{Pd}{⟶} {CH}_{3} - {CH}_{3}$

The ΔH_reaction is written as Calculate ΔH_reaction for

ΔH_reaction= 4ΔH_C−H+ ΔH_C=C+ ΔH_H−H− 6ΔH_H−H−2ΔH_C−C

ΔH_reaction= 4ΔH_C−H+ 2ΔH_C−C+ ΔH_H−H− 6ΔH_C−H− ΔH_C−C

ΔH_reaction= 4ΔH_C−H+ ΔH_C=C+ ΔH_H−H− 6ΔH_C−H− ΔH_C−C

ΔH_reaction= ΔH_C−H+ ΔH_C=C+ ΔH_H−H− ΔH_C−H− ΔH_C−C

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Bonds Broken :-

4 C – H, 1C = C, 1H – H

6C – H, 1C – C
Bonds formed

∴ ΔH_r = 4ΔH_C_–_H+ ΔH_C₌_C + ΔH_H_–_H– 6ΔH_C_–_H – ΔH_C_–_C

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