Given that
Diagram. lee
Each has resistance 3Ω
To Find R_PQ and R_xy
For R_PQ, 6Ω and 3Ω are in parallel
∴ ${\mathrm{R}}_{\mathrm{PQ}}=\frac{6\times 3}{6+3}=\frac{18}{9}=2\mathrm{\Omega }$
For R_xy, 6Ω and 3Ω are in parallel and then all are in series
∴ R_xy = 3 + 2 + 3 = 8Ω
Hence correct answer is 2, 8