Figure shows the kinetic energy K of a simple pendulum versus its angle θ from the vertical. The pendulum bob has mass 0.2 kg. The length of the pendulum is equal to

Engineering

Physics

Simple Harmonic Motion

Question

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$\frac{1}{2} {mv}_{m}^{2} = 15 \times 10^{- 3}$

$V_{m} = \sqrt{0.150} m / s$

$Aω = \sqrt{0 .150} m / s$

${Lq}_{m} \cdot \sqrt{\frac{g}{L}} = \sqrt{0 .150} m / s$

$\sqrt{gL} = \frac{\sqrt{0 .150}}{100 \times 10^{- 3}} \Rightarrow L = \frac{0 .150}{0 .1} = 1 .5 m$

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