Molecular weight of

aniline = M.wt. of C₆NH₇

           = 72 + 7 + 14 = 93

density of P = 1 g mL^–1

9.3 mL of P = 9.3 g P

                   $=\frac{9.3}{9.3}=0.1\mathrm{mol}\mathrm{P}$

                                    = 1 : 1 : 1

so the mole of Q formed will be 0.1 mole and extent of reaction is 100% but if it is 75% yield.

Then amount of Q $=0.1\times \frac{75}{100}=0.075\mathrm{mol}$

The molecular formula of Q = C₁₆H₁₂ON₂

so M.wt. of Q = 16 × 12 + 12 × 1 + 16 + 2 × 14

                      = 192 + 12 + 16 + 28

                      = 248 g

so amount of Q = 248 × 0.075

                         = 18.6 g