Consider a triangular surface whose vertices are three points having co-ordinate A (2a, 0, 0), B (0, a, 0), C(0, 0, a). If there is a uniform electric field E_{0} \hat{i} + 2 E_{0} \hat{j} + 3 E_{0} \hat{k} then flux linked to triangular surface ABC is :

Engineering

Physics

Electric Field and Gauss Law

Question

Consider a triangular surface whose vertices are three points having co-ordinate A (2a, 0, 0), B (0, a, 0), C(0, 0, a). If there is a uniform electric field $E_{0} \hat{i} + 2 E_{0} \hat{j} + 3 E_{0} \hat{k}$ then flux linked to triangular surface ABC is :

$\frac{7 E_{0} a^{2}}{2}$

$\frac{11 E_{0} a^{2}}{2}$

Zero

3E₀a²

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$ϕ = E_{0} \times \frac{1}{2} a^{2} + 2 E_{0} \times \frac{1}{2} \times 2 a^{2}$

$+ 3 E_{0} \times \frac{1}{2} \times 3 a^{2}$

$= \frac{11}{2} E_{0} a^{2}$

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