Adsorption of a gas follows Freundlich adsorption isotherm. x is the mass of the gas adsorbed on mass m of the adsorbent. The plot of log \frac{x}{m} versus log p is shown in the given graph. \frac{x}{m} is proportional to

Engineering

Chemistry

Freundlich Adsorption

Question

Adsorption of a gas follows Freundlich adsorption isotherm. x is the mass of the gas adsorbed on mass m of the adsorbent. The plot of log $\frac{x}{m}$ versus log p is shown in the given graph. $\frac{x}{m}$ is proportional to

p^3/2

p³

p²

p^2/3

LiveFree JEE Main Previous Year Online Papers Live Free JEE Advance Previous Year Online Papers

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

$\frac{x}{m} = {Kp}^{1 / n}$

Taking log from both sides

$∴ \log \frac{x}{m} = logK + \frac{1}{n} logP$

$slope = \frac{1}{n} = \frac{2}{3}$

$∴ \frac{x}{m} = {Kp}^{2 / 3}$

Please subscribe our Youtube channel to unlock this solution.