Engineering
Chemistry
Solubility Chart
Question

A white solid A reacts with dilute H2SO4 to produce a colourless gas B and a colourless solution C. The reaction between B and acidified dichromate yields a green solution and a slightly coloured precipitate D. The substance D, when burnt in air, gives a gas E which reacts wih B to yield D and a colourless liquids. Anhydrous copper sulphate turns blue with this colourless liquid. The addition of aqueous NH3 or NaOH to C produces a precipitate that dissolves in an excess of the reagent to form a clear solution.
Answer the following questions based on above passage.

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Linked Question 1

Suppose the solution obtained by the treatment of the solution C with an excess of NaOH is acidified with acetic acid and the gas B is passed through it. Which of the following will obtained?

Yellow precipitate

Black precipitate

Colourless solution

White precipitate

Solution
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Pb2+ + H2S → PbS + 2H+
                         Black
[Zn(OH)4]2– + 4CH3COOH → Zn++ + 4CH3COO¯ + 4H2O
Zn++ + H2S → ZnS + 2H+

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Linked Question 2

Which of the following gases are B and E respectively?

SO2 and H2S

CO2 and SO2

H2S and SO2

CO2 and H2S

Solution
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Pb2+ + H2S → PbS + 2H+
                        Black
[Zn(OH)4]2– + 4CH3COOH → Zn++ + 4CH3COO¯ + 4H2O
Zn++ + H2S → ZnS + 2H+

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Linked Question 3

What would appear if the gas B is passed through an aqueous solution of Pb(NO3)2?

A black precipitate soluble in hot dilute HNO3

A black precipitate insoluble in hot dilute HNO3

white precipitate soluble in hot dilute HNO3

A yellow precipitate soluble in hot concentrated HNO3 

Solution
Verified BY
Verified by Zigyan

Pb2+ + H2S → PbS + 2H+
                        Black
[Zn(OH)4]2– + 4CH3COOH → Zn++ + 4CH3COO¯ + 4H2O
Zn++ + H2S → ZnS + 2H+

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Please subscribe our Youtube channel to unlock this solution.