A non conducting ring uniformly charge as shown is placed in electric field \overset{\rightarrow}{E} = E_{0} \hat{i} \textrm{ } + \textrm{ } 2 E_{0} \hat{j}. Electric force on charged ring will be

Engineering

Physics

Electric Dipole

Question

A non conducting ring uniformly charge as shown is placed in electric field $\vec{E} = E_{0} \hat{i} + 2 E_{0} \hat{j}$ . Electric force on charged ring will be

Zero

$\frac{4 Rq}{π} E_{0}$

$\frac{4 Rq}{π} E_{0} \sqrt{5}$

$\frac{2 R}{π} {qE}_{0}$

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Force on dipole in uniform field is zero.

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