A light ray in water strikes the water surface at an angle of 60° to the normal. The path of the ray after striking is :

Engineering

Physics

Reflection at Plane Surface

Question

None of these

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$\frac{4}{3} \sin 60^{\circ} = \frac{4}{3} \times \frac{\sqrt{3}}{2} = \frac{2}{\sqrt{3}} > 1 \sin 90^{\circ}$
⇒ Ray will undergo TIR

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