A hollow cone is filled with water as shown in figure-1. The force exerted by the water on cone is F. Now the cone is inverted and kept on a table as shown in figure-2. Neglect atmospheric pressure. No water leaks out. The force exerted by water on cone is now

Engineering

Physics

Statics

Question

F downwards

$\frac{F}{2}$ upwards

F upwards

2F upwards

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$F = W = P \frac{1}{3} {πR}^{2} H$

$F^{'} + W = PA \Rightarrow P = ρgh \Rightarrow PA = {ρgHπR}^{2}$

$F^{'} = \frac{2}{3} {ρπR}^{2} H = 2 F$

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