Engineering
Physics
Physical Quantities
Question

A gas is enclosed in a cylinder with a movable frictionless piston. Its initial thermodynamic state at pressure Pi = 105 Pa and volume Vi = 10–3 m3 changes to a final state at Pf = (l/32) × 105 Pa  and Vf = 8 × 10–3 m3 in an adiabatic quasi-static process, such that P3V5 = constant. Consider another thermodynamic process that brings the system from the same initial state to the same final state in two steps: an isobaric expansion at Pi followed by an isochoric (isovolumetric) process at volume Vf. The amount of heat supplied to the system in the two-step process is approximately

588 J

813 J

294 J

112 J

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Solution
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P0V0γ=P032(8V0)γ

25 = 2

3γ = 5

dQ = dUif + dWif

=nPdTγ1+P0×7V0=PfVfPiViγ1+P0×7V0

=P032×8V0P0V0531+7P0V0=P0V04P0V023

=32(3P0V04)+7P0V0=98P0V0+7P0V0

=(569)P0V08=478P0V0=478×105×103

 =478×100

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