${\mathrm{P}}_{\mathrm{far}}=\frac{1}{\mathrm{f}}=\frac{1}{1.25}+\frac{1}{0.02}=+50.8 \mathrm{Diopters}$
Similarly, when eye is focused on object at near point, the optical power of lens cornea combination is 
${\mathrm{P}}_{\mathrm{near}}=\frac{1}{\mathrm{f}}=\frac{1}{0.1}+\frac{1}{0.020}=+60 \mathrm{Diopters}$
Hence, the range of the power of lens cornea combination is + 50.8 Diopters ≤ P ≤ 60.0 Diopters 
(b) if child sees very distant object clearly, her eyeglass lens must form an erect, virtual image for the object at infinity at the far point of her eye, optical power of required lens is,
$\mathrm{P}=\frac{1}{\mathrm{u}}+\frac{1}{\mathrm{v}}=0+\frac{1}{-0.125}=-0.8000 \mathrm{Diopters}$

Since the power and hence the focal length of this lens is -ve, it is diverging.